In the Reds’ 4 – 1 victory over Pirates, two sets of brothers appear in the same lineup for the first time in major league history

On September 27, 1998 — In the Reds’ 4 – 1 victory over Pirates, two sets of brothers appear in the same lineup for the first time in major league history. Stephen Larkin plays first, Bret Boone is at second, Barry Larkin is at short and Aaron Boone plays third making up the all-brother infield. Aaron Boone’s 3-run homer gives Brett Tomko (13-12) the complete game victory. Stephen Larkin is a career minor leaguer with a pacemaker and had a new one installed in August after his old one had a hiccup. Stephen hit .228 with three home run and 31 RBI in 80 games with the AA Chattanooga Lookouts this year.

 

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