Ted Williams hits 3 home runs to over shadow a 5-5 from Lou Boudreau

ted williams

On July 14, 1946, Lou Boudreau of the Cleveland Indians collects four doubles and a home run in the first game of a doubleheader against the Boston Red Sox. Ted Williams overshadows Boudreau by hitting three homers and driving in eight runs to lead the Sox to an 11-10 win. In the Sox’s second-game win, the famous Boudreau Shift is born. Boudreau shifts all his players, except the 3B and LF, to the right side of the diamond in an effort to stop Williams. Ted grounds out and walks twice while ignoring the shift.
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